5d^2-44d+90=0

Solution for 5d^2-44d+90=0 equation:

5d^2-44d+90=0

a = 5; b = -44; c = +90;
Δ = b2-4ac
Δ = -442-4·5·90
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{34}}{2*5}=\frac{44-2\sqrt{34}}{10}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{34}}{2*5}=\frac{44+2\sqrt{34}}{10}
$